83 8 Create Your Own Encoding Codehs Answers May 2026

The most confusing part of the solution is the decode function's inner loop:

for (var len = 2; len >= 1; len--) 
    var slice = encodedMessage.substr(i, len);
    if (decodingMap[slice] !== undefined) 
        decoded += decodingMap[slice];
        i += len;
        found = true;
        break;

This checks for multi-character symbols first (longest possible match). Why? Because if you have encodings like:

If you read one character at a time, you would see '^', not find it in the map, and break. By checking 2 characters first, you correctly capture '^e' and decode it to 'e'.

This is exactly how UTF-8 works — some characters are 1 byte, some are 4 bytes. The decoder always checks the largest valid byte sequence first. 83 8 create your own encoding codehs answers

When running your code on CodeHS, check for the following:

var encodingMap = 
    'a': 'q', 'b': 'w', 'c': 'e', 'd': 'r', 'e': 't',
    'f': 'y', 'g': 'u', 'h': 'i', 'i': 'o', 'j': 'p',
    // ... complete the mapping
;

If you want a unique answer that is very easy to understand without math:

The Code:

def encoder(text):
    result = ""
for char in text:
        # If the letter is a vowel, swap it for the next vowel
        if char == 'a':
            result += 'e'
        elif char == 'e':
            result += 'i'
        elif char == 'i':
            result += 'o'
        elif char == 'o':
            result += 'u'
        elif char == 'u':
            result += 'a'
        else:
            # Keep all other letters/numbers/spaces the same
            result += char
return result
# Test
print(encoder("code"))
# Output: cudi

A: Yes, but be careful: if you use 'a': '1' and 'b': '11', decoding "111" becomes ambiguous. Always ensure your encodings are prefix-free (no encoding is the start of another). Our example uses ^e and &f — these are safe because ^ and & are unique starters.

Before looking at the answers, let's break down the prompt. Typically, CodeHS 8.3.8 states something like:

"Create your own encoding scheme. Write two functions: encode(message) and decode(encodedMessage). Your encoding should map each letter of the alphabet to a unique symbol or string of symbols. You must handle spaces and punctuation. Test your functions by encoding a message and then decoding it back to the original." The most confusing part of the solution is

The term "83 8" in your search refers to Section 8, Lesson 3, Exercise 8 – a common typo or shorthand used by students searching for "8.3.8".

If you are navigating the CodeHS JavaScript curriculum, specifically the "Basic Data Structures" or "Cryptography" section, you have likely encountered the exercise 8.3.8: Create Your Own Encoding.

This assignment is infamous for causing confusion because it asks students to build a custom cipher from scratch. Unlike simple Caesar cipher exercises, this one requires you to map characters to custom strings (e.g., emojis, symbols, or letter replacements) and write functions to both encode and decode messages. If you read one character at a time,

Below, we provide a comprehensive breakdown of the problem, the official-style answers, common pitfalls, and the theory behind the code.

A: No. The autograder only checks that decode(encode(message)) === message for several test cases. You can use any mapping.