A trapezoidal channel with ( b = 2 ) m, side slope 1:1, ( y_n = 1.2 ) m, ( n = 0.025 ), ( S_0 = 0.001 ) carries a discharge:
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Chow derived conditions for the most hydraulically efficient section (minimum wetted perimeter ( P ) for a given area ( A ), hence maximum ( R )): A trapezoidal channel with ( b = 2
| Shape | Optimal proportions | |-------|---------------------| | Rectangle | Depth = half the bottom width (( y = b/2 )) | | Trapezoid (side slope ( z:1 )) | Half of the top width equals the sloped side length, giving ( y = \fracb2 \sqrt1+z^2 - z ) | | Triangle (45°) | Minimum ( P ) occurs at ( \theta = 45^\circ ) for V-shaped section | side slope 1:1