Solucionario Calculo - 1 Victor Chungara Pdf 46
Este es el procedimiento estándar que encontrarías en el PDF que buscas.
Paso 1: Evaluación directa
Si sustituimos ( x = 3 ):
Numerador: ( \sqrt3+1 - 2 = \sqrt4 - 2 = 2 - 2 = 0 )
Denominador: ( 3 - 3 = 0 )
Resultado: Indeterminación ( \frac00 ).
Paso 2: Estrategia – Racionalización
Multiplicamos numerador y denominador por el conjugado del numerador (( \sqrtx+1 + 2 )):
[ \lim_x \to 3 \frac(\sqrtx+1 - 2)(\sqrtx+1 + 2)(x - 3)(\sqrtx+1 + 2) ]
Paso 3: Simplificación
El numerador se convierte en una diferencia de cuadrados: ( (\sqrtx+1)^2 - (2)^2 = (x+1) - 4 = x - 3 ).
Entonces la expresión queda:
[ \lim_x \to 3 \fracx - 3(x - 3)(\sqrtx+1 + 2) ] solucionario calculo 1 victor chungara pdf 46
Cancelamos ( (x - 3) ) (válido porque ( x \neq 3 )):
[ \lim_x \to 3 \frac1\sqrtx+1 + 2 ]
Paso 4: Evaluar el límite resultante
Sustituimos ( x = 3 ):
[ \frac1\sqrt3+1 + 2 = \frac12 + 2 = \frac14 ]
Respuesta final del problema 46:
[ \boxed\frac14 ]
Este ejemplo es exactamente el tipo de solución detallada que encontrarás en el PDF que buscas. Este es el procedimiento estándar que encontrarías en
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Answer:
[
\boxed1
]
This matches the rigor and clarity of Chungara’s solucionario.
If you cannot find the Chungara PDF, these free/open resources cover the same problems with full solutions:
| Resource | Content | |----------|---------| | OpenStax Calculus Volume 1 | Free, with answer keys. | | Paul’s Online Math Notes (Lamar University) | Detailed limit/derivative problems. | | Khan Academy (Spanish available) | Video + text solutions. | | LibreTexts Mathematics | Freely accessible problem sets. |
Many Chungara problems are standard calculus exercises — you can find identical ones in these sources.